LeetCode in Kotlin

3813. Vowel-Consonant Score

Easy

You are given a string s consisting of lowercase English letters, spaces, and digits.

Let v be the number of vowels in s and c be the number of consonants in s.

A vowel is one of the letters 'a', 'e', 'i', 'o', or 'u', while any other letter in the English alphabet is considered a consonant.

The score of the string s is defined as follows:

• If c > 0, the score = floor(v / c) where floor denotes rounding down to the nearest integer.
• Otherwise, the score = 0.

Return an integer denoting the score of the string.

Example 1:

Input: s = “cooear”

Output: 2

Explanation:

The string s = "cooear" contains v = 4 vowels ('o', 'o', 'e', 'a') and c = 2 consonants ('c', 'r').

The score is floor(v / c) = floor(4 / 2) = 2.

Example 2:

Input: s = “axeyizou”

Output: 1

Explanation:

The string s = "axeyizou" contains v = 5 vowels ('a', 'e', 'i', 'o', 'u') and c = 3 consonants ('x', 'y', 'z').

The score is floor(v / c) = floor(5 / 3) = 1.

Example 3:

Input: s = “au 123”

Output: 0

Explanation:

The string s = "au 123" contains no consonants (c = 0), so the score is 0.

Constraints:

• 1 <= s.length <= 100
• s consists of lowercase English letters, spaces and digits.

Solution

class Solution {
    fun vowelConsonantScore(s: String): Int {
        var count = 0
        val vowels = "aeiou"
        var con = 0
        for (ch in s.toCharArray()) {
            if (vowels.indexOf(ch) != -1) {
                count++
                continue
            }
            if (Character.isAlphabetic(ch.code)) {
                con++
            }
        }
        return if (con == 0) 0 else count / con
    }
}

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