Medium
You are given an integer array nums of size n containing only 1 and -1, and an integer k.
You can perform the following operation at most k times:
i (0 <= i < n - 1), and multiply both nums[i] and nums[i + 1] by -1.Note that you can choose the same index i more than once in different operations.
Return true if it is possible to make all elements of the array equal after at most k operations, and false otherwise.
Example 1:
Input: nums = [1,-1,1,-1,1], k = 3
Output: true
Explanation:
We can make all elements in the array equal in 2 operations as follows:
i = 1, and multiply both nums[1] and nums[2] by -1. Now nums = [1,1,-1,-1,1].i = 2, and multiply both nums[2] and nums[3] by -1. Now nums = [1,1,1,1,1].Example 2:
Input: nums = [-1,-1,-1,1,1,1], k = 5
Output: false
Explanation:
It is not possible to make all array elements equal in at most 5 operations.
Constraints:
1 <= n == nums.length <= 105nums[i] is either -1 or 1.1 <= k <= nclass Solution {
fun canMakeEqual(nums: IntArray, k: Int): Boolean {
val n = nums.size
if (n == 1) {
return true
}
var prod = 1
for (x in nums) {
prod *= x
}
val targets: MutableList<Int> = ArrayList<Int>()
for (target in intArrayOf(1, -1)) {
val tPowN = (if (n % 2 == 0) 1 else target)
if (tPowN == prod) {
targets.add(target)
}
}
if (targets.isEmpty()) {
return false
}
for (target in targets) {
var ops = 0
val a = nums.clone()
var i = 0
while (i < n - 1 && ops <= k) {
if (a[i] != target) {
a[i] = -a[i]
a[i + 1] = -a[i + 1]
ops++
}
i++
}
if (ops <= k && a[n - 1] == target) {
return true
}
}
return false
}
}