LeetCode in Kotlin

3522. Calculate Score After Performing Instructions

Medium

You are given two arrays, instructions and values, both of size n.

You need to simulate a process based on the following rules:

• You start at the first instruction at index i = 0 with an initial score of 0.
• If instructions[i] is "add":
  • Add values[i] to your score.
  • Move to the next instruction (i + 1).
• If instructions[i] is "jump":
  • Move to the instruction at index (i + values[i]) without modifying your score.

The process ends when you either:

• Go out of bounds (i.e., i < 0 or i >= n), or
• Attempt to revisit an instruction that has been previously executed. The revisited instruction is not executed.

Return your score at the end of the process.

Example 1:

Input: instructions = [“jump”,”add”,”add”,”jump”,”add”,”jump”], values = [2,1,3,1,-2,-3]

Output: 1

Explanation:

Simulate the process starting at instruction 0:

• At index 0: Instruction is "jump", move to index 0 + 2 = 2.
• At index 2: Instruction is "add", add values[2] = 3 to your score and move to index 3. Your score becomes 3.
• At index 3: Instruction is "jump", move to index 3 + 1 = 4.
• At index 4: Instruction is "add", add values[4] = -2 to your score and move to index 5. Your score becomes 1.
• At index 5: Instruction is "jump", move to index 5 + (-3) = 2.
• At index 2: Already visited. The process ends.

Example 2:

Input: instructions = [“jump”,”add”,”add”], values = [3,1,1]

Output: 0

Explanation:

Simulate the process starting at instruction 0:

• At index 0: Instruction is "jump", move to index 0 + 3 = 3.
• At index 3: Out of bounds. The process ends.

Example 3:

Input: instructions = [“jump”], values = [0]

Output: 0

Explanation:

Simulate the process starting at instruction 0:

• At index 0: Instruction is "jump", move to index 0 + 0 = 0.
• At index 0: Already visited. The process ends.

Constraints:

• n == instructions.length == values.length
• 1 <= n <= 105
• instructions[i] is either "add" or "jump".
• -105 <= values[i] <= 105

Solution

class Solution {
    fun calculateScore(instructions: Array<String>, values: IntArray): Long {
        var ans: Long = 0
        val seen = BooleanArray(instructions.size)
        var pos = 0
        while (pos >= 0 && pos < instructions.size && !seen[pos]) {
            seen[pos] = true
            if (instructions[pos][0] == 'a') {
                ans += values[pos].toLong()
                pos++
            } else {
                pos += values[pos]
            }
        }
        return ans
    }
}

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