LeetCode in Kotlin
3516. Find Closest Person
Easy
You are given three integers x, y, and z, representing the positions of three people on a number line:
xis the position of Person 1.yis the position of Person 2.zis the position of Person 3, who does not move.
Both Person 1 and Person 2 move toward Person 3 at the same speed.
Determine which person reaches Person 3 first:
- Return 1 if Person 1 arrives first.
- Return 2 if Person 2 arrives first.
- Return 0 if both arrive at the same time.
Return the result accordingly.
Example 1:
Input: x = 2, y = 7, z = 4
Output: 1
Explanation:
- Person 1 is at position 2 and can reach Person 3 (at position 4) in 2 steps.
- Person 2 is at position 7 and can reach Person 3 in 3 steps.
Since Person 1 reaches Person 3 first, the output is 1.
Example 2:
Input: x = 2, y = 5, z = 6
Output: 2
Explanation:
- Person 1 is at position 2 and can reach Person 3 (at position 6) in 4 steps.
- Person 2 is at position 5 and can reach Person 3 in 1 step.
Since Person 2 reaches Person 3 first, the output is 2.
Example 3:
Input: x = 1, y = 5, z = 3
Output: 0
Explanation:
- Person 1 is at position 1 and can reach Person 3 (at position 3) in 2 steps.
- Person 2 is at position 5 and can reach Person 3 in 2 steps.
Since both Person 1 and Person 2 reach Person 3 at the same time, the output is 0.
Constraints:
1 <= x, y, z <= 100
Solution
import kotlin.math.abs
class Solution {
fun findClosest(x: Int, y: Int, z: Int): Int {
val d1 = abs(z - x)
val d2 = abs(z - y)
return if (d1 == d2) {
0
} else if (d1 < d2) {
1
} else {
2
}
}
}