LeetCode in Kotlin

3467. Transform Array by Parity

Easy

You are given an integer array nums. Transform nums by performing the following operations in the exact order specified:

1. Replace each even number with 0.
2. Replace each odd numbers with 1.
3. Sort the modified array in non-decreasing order.

Return the resulting array after performing these operations.

Example 1:

Input: nums = [4,3,2,1]

Output: [0,0,1,1]

Explanation:

• Replace the even numbers (4 and 2) with 0 and the odd numbers (3 and 1) with 1. Now, nums = [0, 1, 0, 1].
• After sorting nums in non-descending order, nums = [0, 0, 1, 1].

Example 2:

Input: nums = [1,5,1,4,2]

Output: [0,0,1,1,1]

Explanation:

• Replace the even numbers (4 and 2) with 0 and the odd numbers (1, 5 and 1) with 1. Now, nums = [1, 1, 1, 0, 0].
• After sorting nums in non-descending order, nums = [0, 0, 1, 1, 1].

Constraints:

• 1 <= nums.length <= 100
• 1 <= nums[i] <= 1000

Solution

class Solution {
    fun transformArray(nums: IntArray): IntArray {
        val size = nums.size
        val ans = IntArray(size)
        var countEven = 0
        for (i in nums.indices) {
            if (nums[i] and 1 == 0) {
                countEven++
            }
        }
        for (i in countEven until size) {
            ans[i] = 1
        }
        return ans
    }
}

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