LeetCode in Kotlin
3285. Find Indices of Stable Mountains
Easy
There are n mountains in a row, and each mountain has a height. You are given an integer array height where height[i] represents the height of mountain i, and an integer threshold.
A mountain is called stable if the mountain just before it (if it exists) has a height strictly greater than threshold. Note that mountain 0 is not stable.
Return an array containing the indices of all stable mountains in any order.
Example 1:
Input: height = [1,2,3,4,5], threshold = 2
Output: [3,4]
Explanation:
- Mountain 3 is stable because
height[2] == 3is greater thanthreshold == 2. - Mountain 4 is stable because
height[3] == 4is greater thanthreshold == 2.
Example 2:
Input: height = [10,1,10,1,10], threshold = 3
Output: [1,3]
Example 3:
Input: height = [10,1,10,1,10], threshold = 10
Output: []
Constraints:
2 <= n == height.length <= 1001 <= height[i] <= 1001 <= threshold <= 100
Solution
class Solution {
fun stableMountains(height: IntArray, threshold: Int): List<Int> {
val n = height.size
val list: MutableList<Int> = mutableListOf()
for (i in 0 until n - 1) {
if (height[i] > threshold) {
list.add(i + 1)
}
}
return list
}
}