LeetCode in Kotlin

3243. Shortest Distance After Road Addition Queries I

Medium

You are given an integer n and a 2D integer array queries.

There are n cities numbered from 0 to n - 1. Initially, there is a unidirectional road from city i to city i + 1 for all 0 <= i < n - 1.

queries[i] = [ui, vi] represents the addition of a new unidirectional road from city ui to city vi. After each query, you need to find the length of the shortest path from city 0 to city n - 1.

Return an array answer where for each i in the range [0, queries.length - 1], answer[i] is the length of the shortest path from city 0 to city n - 1 after processing the first i + 1 queries.

Example 1:

Input: n = 5, queries = [[2,4],[0,2],[0,4]]

Output: [3,2,1]

Explanation:

After the addition of the road from 2 to 4, the length of the shortest path from 0 to 4 is 3.

After the addition of the road from 0 to 2, the length of the shortest path from 0 to 4 is 2.

After the addition of the road from 0 to 4, the length of the shortest path from 0 to 4 is 1.

Example 2:

Input: n = 4, queries = [[0,3],[0,2]]

Output: [1,1]

Explanation:

After the addition of the road from 0 to 3, the length of the shortest path from 0 to 3 is 1.

After the addition of the road from 0 to 2, the length of the shortest path remains 1.

Constraints:

Solution

class Solution {
    fun shortestDistanceAfterQueries(n: Int, queries: Array<IntArray>): IntArray {
        val dist = IntArray(n)
        for (i in 0 until n) {
            dist[i] = i
        }
        val parent: Array<ArrayList<Int>> = Array(n) { ArrayList() }
        for (i in 0 until n) {
            parent[i] = ArrayList()
            if (i != n - 1) {
                parent[i].add(i + 1)
            }
        }
        val ans = IntArray(queries.size)
        for (i in queries.indices) {
            val u = queries[i][0]
            val v = queries[i][1]
            if (dist[v] > dist[u] + 1) {
                dist[v] = dist[u] + 1
                parent[u].add(v)
                updateDistance(v, dist, parent)
            } else {
                parent[u].add(v)
            }
            ans[i] = dist[n - 1]
        }
        return ans
    }

    fun updateDistance(par: Int, dist: IntArray, parent: Array<ArrayList<Int>>) {
        for (i in parent[par].indices) {
            val child = parent[par][i]
            if (dist[child] > dist[par] + 1) {
                dist[child] = dist[par] + 1
                updateDistance(child, dist, parent)
            }
        }
    }
}