LeetCode in Kotlin
3131. Find the Integer Added to Array I
Easy
You are given two arrays of equal length, nums1 and nums2.
Each element in nums1 has been increased (or decreased in the case of negative) by an integer, represented by the variable x.
As a result, nums1 becomes equal to nums2. Two arrays are considered equal when they contain the same integers with the same frequencies.
Return the integer x.
Example 1:
Input: nums1 = [2,6,4], nums2 = [9,7,5]
Output: 3
Explanation:
The integer added to each element of nums1 is 3.
Example 2:
Input: nums1 = [10], nums2 = [5]
Output: -5
Explanation:
The integer added to each element of nums1 is -5.
Example 3:
Input: nums1 = [1,1,1,1], nums2 = [1,1,1,1]
Output: 0
Explanation:
The integer added to each element of nums1 is 0.
Constraints:
1 <= nums1.length == nums2.length <= 1000 <= nums1[i], nums2[i] <= 1000- The test cases are generated in a way that there is an integer
xsuch thatnums1can become equal tonums2by addingxto each element ofnums1.
Solution
class Solution {
fun addedInteger(nums1: IntArray, nums2: IntArray): Int {
val n1 = nums1.size
var s1 = 0
var s2 = 0
for (i in nums1) {
s1 += i
}
for (i in nums2) {
s2 += i
}
return (s2 - s1) / n1
}
}