Easy
You are given a string word
. A letter is called special if it appears both in lowercase and uppercase in word
.
Return the number of special letters in word
.
Example 1:
Input: word = “aaAbcBC”
Output: 3
Explanation:
The special characters in word
are 'a'
, 'b'
, and 'c'
.
Example 2:
Input: word = “abc”
Output: 0
Explanation:
No character in word
appears in uppercase.
Example 3:
Input: word = “abBCab”
Output: 1
Explanation:
The only special character in word
is 'b'
.
Constraints:
1 <= word.length <= 50
word
consists of only lowercase and uppercase English letters.class Solution {
fun numberOfSpecialChars(word: String): Int {
val a = IntArray(26)
val b = IntArray(26)
var ans = 0
for (c in word.toCharArray()) {
if (c in 'a'..'z') {
a[c.code - 'a'.code]++
} else {
b[c.code - 'A'.code]++
}
}
for (i in 0..25) {
if (a[i] != 0 && b[i] != 0) {
ans++
}
}
return ans
}
}