LeetCode in Kotlin

3095. Shortest Subarray With OR at Least K I

Easy

You are given an array nums of non-negative integers and an integer k.

An array is called special if the bitwise OR of all of its elements is at least k.

Return the length of the shortest special non-empty subarray of nums, or return -1 if no special subarray exists.

Example 1:

Input: nums = [1,2,3], k = 2

Output: 1

Explanation:

The subarray [3] has OR value of 3. Hence, we return 1.

Example 2:

Input: nums = [2,1,8], k = 10

Output: 3

Explanation:

The subarray [2,1,8] has OR value of 11. Hence, we return 3.

Example 3:

Input: nums = [1,2], k = 0

Output: 1

Explanation:

The subarray [1] has OR value of 1. Hence, we return 1.

Constraints:

• 1 <= nums.length <= 50
• 0 <= nums[i] <= 50
• 0 <= k < 64

Solution

import kotlin.math.min

class Solution {
    fun minimumSubarrayLength(nums: IntArray, k: Int): Int {
        val n = nums.size
        var maxL = n + 1
        var `val`: Int
        for (i in 0 until n) {
            `val` = 0
            for (j in i until n) {
                `val` = `val` or nums[j]
                if (`val` >= k) {
                    maxL = min(maxL, (j - i + 1))
                }
            }
        }
        return if (maxL == n + 1) -1 else maxL
    }
}

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