Hard
There exists an undirected tree with n
nodes numbered 0
to n - 1
. You are given a 0-indexed 2D integer array edges
of length n - 1
, where edges[i] = [ui, vi]
indicates that there is an edge between nodes ui
and vi
in the tree. You are also given a positive integer k
, and a 0-indexed array of non-negative integers nums
of length n
, where nums[i]
represents the value of the node numbered i
.
Alice wants the sum of values of tree nodes to be maximum, for which Alice can perform the following operation any number of times (including zero) on the tree:
[u, v]
connecting the nodes u
and v
, and update their values as follows:
nums[u] = nums[u] XOR k
nums[v] = nums[v] XOR k
Return the maximum possible sum of the values Alice can achieve by performing the operation any number of times.
Example 1:
Input: nums = [1,2,1], k = 3, edges = [[0,1],[0,2]]
Output: 6
Explanation: Alice can achieve the maximum sum of 6 using a single operation:
The total sum of values is 2 + 2 + 2 = 6.
It can be shown that 6 is the maximum achievable sum of values.
Example 2:
Input: nums = [2,3], k = 7, edges = [[0,1]]
Output: 9
Explanation: Alice can achieve the maximum sum of 9 using a single operation:
The total sum of values is 5 + 4 = 9.
It can be shown that 9 is the maximum achievable sum of values.
Example 3:
Input: nums = [7,7,7,7,7,7], k = 3, edges = [[0,1],[0,2],[0,3],[0,4],[0,5]]
Output: 42
Explanation: The maximum achievable sum is 42 which can be achieved by Alice performing no operations.
Constraints:
2 <= n == nums.length <= 2 * 104
1 <= k <= 109
0 <= nums[i] <= 109
edges.length == n - 1
edges[i].length == 2
0 <= edges[i][0], edges[i][1] <= n - 1
edges
represent a valid tree.import kotlin.math.abs
import kotlin.math.max
import kotlin.math.min
@Suppress("UNUSED_PARAMETER")
class Solution {
fun maximumValueSum(nums: IntArray, k: Int, edges: Array<IntArray>): Long {
var res: Long = 0
var d = 1 shl 30
var c = 0
for (a in nums) {
val b = a xor k
res += max(a, b)
c = c xor if (a < b) 1 else 0
d = min(d, abs((a - b)))
}
return res - d * c
}
}