Easy
You are given a 0-indexed integer array nums
of size 3
which can form the sides of a triangle.
Return a string representing the type of triangle that can be formed or "none"
if it cannot form a triangle.
Example 1:
Input: nums = [3,3,3]
Output: “equilateral”
Explanation: Since all the sides are of equal length, therefore, it will form an equilateral triangle.
Example 2:
Input: nums = [3,4,5]
Output: “scalene”
Explanation:
nums[0] + nums[1] = 3 + 4 = 7, which is greater than nums[2] = 5.
nums[0] + nums[2] = 3 + 5 = 8, which is greater than nums[1] = 4.
nums[1] + nums[2] = 4 + 5 = 9, which is greater than nums[0] = 3.
Since the sum of the two sides is greater than the third side for all three cases, therefore, it can form a triangle.
As all the sides are of different lengths, it will form a scalene triangle.
Constraints:
nums.length == 3
1 <= nums[i] <= 100
class Solution {
fun triangleType(nums: IntArray): String {
if (nums[0] + nums[1] > nums[2] && nums[1] + nums[2] > nums[0] && nums[2] + nums[0] > nums[1]) {
return if (nums[0] == nums[1] && nums[1] == nums[2]) {
"equilateral"
} else if (nums[0] == nums[1] || nums[0] == nums[2] || nums[2] == nums[1]) {
"isosceles"
} else {
"scalene"
}
}
return "none"
}
}