LeetCode in Kotlin

2982. Find Longest Special Substring That Occurs Thrice II

Medium

You are given a string s that consists of lowercase English letters.

A string is called special if it is made up of only a single character. For example, the string "abc" is not special, whereas the strings "ddd", "zz", and "f" are special.

Return the length of the longest special substring of s which occurs at least thrice, or -1 if no special substring occurs at least thrice.

A substring is a contiguous non-empty sequence of characters within a string.

Example 1:

Input: s = “aaaa”

Output: 2

Explanation: The longest special substring which occurs thrice is “aa”: substrings “aaaa”, “aaaa”, and “aaaa”.

It can be shown that the maximum length achievable is 2.

Example 2:

Input: s = “abcdef”

Output: -1

Explanation: There exists no special substring which occurs at least thrice. Hence return -1.

Example 3:

Input: s = “abcaba”

Output: 1

Explanation: The longest special substring which occurs thrice is “a”: substrings “abcaba”, “abcaba”, and “abcaba”.

It can be shown that the maximum length achievable is 1.

Constraints:

Solution

import kotlin.math.max

class Solution {
    fun maximumLength(s: String): Int {
        val arr = Array(26) { IntArray(4) }
        var prev = s[0]
        var count = 1
        var max = 0
        for (index in 1 until s.length) {
            if (s[index] != prev) {
                val ints = arr[prev.code - 'a'.code]
                updateArr(count, ints)
                prev = s[index]
                count = 1
            } else {
                count++
            }
        }
        updateArr(count, arr[prev.code - 'a'.code])
        for (values in arr) {
            if (values[0] != 0) {
                max = if (values[1] >= 3) {
                    max(max, values[0])
                } else if (values[1] == 2 || values[2] == values[0] - 1) {
                    max(max, (values[0] - 1))
                } else {
                    max(max, (values[0] - 2))
                }
            }
        }
        return if (max == 0) -1 else max
    }

    private fun updateArr(count: Int, ints: IntArray) {
        if (ints[0] == count) {
            ints[1]++
        } else if (ints[0] < count) {
            ints[3] = ints[1]
            ints[2] = ints[0]
            ints[0] = count
            ints[1] = 1
        } else if (ints[2] < count) {
            ints[2] = count
            ints[3] = 1
        }
    }
}