LeetCode in Kotlin
2825. Make String a Subsequence Using Cyclic Increments
Medium
You are given two 0-indexed strings str1 and str2.
In an operation, you select a set of indices in str1, and for each index i in the set, increment str1[i] to the next character cyclically. That is 'a' becomes 'b', 'b' becomes 'c', and so on, and 'z' becomes 'a'.
Return true if it is possible to make str2 a subsequence of str1 by performing the operation at most once, and false otherwise.
Note: A subsequence of a string is a new string that is formed from the original string by deleting some (possibly none) of the characters without disturbing the relative positions of the remaining characters.
Example 1:
Input: str1 = “abc”, str2 = “ad”
Output: true
Explanation: Select index 2 in str1. Increment str1[2] to become ‘d’. Hence, str1 becomes “abd” and str2 is now a subsequence. Therefore, true is returned.
Example 2:
Input: str1 = “zc”, str2 = “ad”
Output: true
Explanation: Select indices 0 and 1 in str1. Increment str1[0] to become ‘a’. Increment str1[1] to become ‘d’. Hence, str1 becomes “ad” and str2 is now a subsequence. Therefore, true is returned.
Example 3:
Input: str1 = “ab”, str2 = “d”
Output: false
Explanation: In this example, it can be shown that it is impossible to make str2 a subsequence of str1 using the operation at most once. Therefore, false is returned.
Constraints:
1 <= str1.length <= 1051 <= str2.length <= 105str1andstr2consist of only lowercase English letters.
Solution
class Solution {
fun canMakeSubsequence(str1: String, str2: String): Boolean {
var str1ptr = 0
for (element in str2) {
val c2 = element
var found = false
while (str1ptr < str1.length) {
val c1 = str1[str1ptr++]
if (c1 == c2 || (c1.code - 'a'.code + 1) % 26 == c2.code - 'a'.code) {
found = true
break
}
}
if (!found) {
return false
}
}
return true
}
}