Easy
Given an integer array nums
containing distinct positive integers, find and return any number from the array that is neither the minimum nor the maximum value in the array, or -1
if there is no such number.
Return the selected integer.
Example 1:
Input: nums = [3,2,1,4]
Output: 2
Explanation: In this example, the minimum value is 1 and the maximum value is 4. Therefore, either 2 or 3 can be valid answers.
Example 2:
Input: nums = [1,2]
Output: -1
Explanation: Since there is no number in nums that is neither the maximum nor the minimum, we cannot select a number that satisfies the given condition. Therefore, there is no answer.
Example 3:
Input: nums = [2,1,3]
Output: 2
Explanation: Since 2 is neither the maximum nor the minimum value in nums, it is the only valid answer.
Constraints:
1 <= nums.length <= 100
1 <= nums[i] <= 100
nums
are distinctclass Solution {
fun findNonMinOrMax(nums: IntArray): Int {
var mn = 999
var mx: Int = -1
nums.forEach {
mn = kotlin.math.min(it, mn)
mx = kotlin.math.max(it, mx)
}
nums.forEach {
if (it != mn && it != mx)return it
}
return -1
}
}