LeetCode in Kotlin

2683. Neighboring Bitwise XOR

Medium

A 0-indexed array derived with length n is derived by computing the bitwise XOR (⊕) of adjacent values in a binary array original of length n.

Specifically, for each index i in the range [0, n - 1]:

• If i = n - 1, then derived[i] = original[i] ⊕ original[0].
• Otherwise, derived[i] = original[i] ⊕ original[i + 1].

Given an array derived, your task is to determine whether there exists a valid binary array original that could have formed derived.

Return true if such an array exists or false otherwise.

• A binary array is an array containing only 0’s and 1’s

Example 1:

Input: derived = [1,1,0]

Output: true

Explanation: A valid original array that gives derived is [0,1,0].

derived[0] = original[0] ⊕ original[1] = 0 ⊕ 1 = 1

derived[1] = original[1] ⊕ original[2] = 1 ⊕ 0 = 1

derived[2] = original[2] ⊕ original[0] = 0 ⊕ 0 = 0

Example 2:

Input: derived = [1,1]

Output: true

Explanation: A valid original array that gives derived is [0,1].

derived[0] = original[0] ⊕ original[1] = 1

derived[1] = original[1] ⊕ original[0] = 1

Example 3:

Input: derived = [1,0]

Output: false

Explanation: There is no valid original array that gives derived.

Constraints:

• n == derived.length
• 1 <= n <= 105
• The values in derived are either 0’s or 1’s

Solution

class Solution {
    fun doesValidArrayExist(derived: IntArray): Boolean {
        var xor = 0
        for (j in derived) {
            xor = xor xor j
        }
        return xor == 0
    }
}

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