Medium
Given a multi-dimensional array of integers, return a generator object which yields integers in the same order as inorder traversal.
A multi-dimensional array is a recursive data structure that contains both integers and other multi-dimensional arrays.
inorder traversal iterates over each array from left to right, yielding any integers it encounters or applying inorder traversal to any arrays it encounters.
Example 1:
Input: arr = [[[6]],[1,3],[]]
Output: [6,1,3]
Explanation:
const generator = inorderTraversal(arr);
generator.next().value; // 6
generator.next().value; // 1
generator.next().value; // 3
generator.next().done; // true
Example 2:
Input: arr = []
Output: []
Explanation: There are no integers so the generator doesn’t yield anything.
Constraints:
0 <= arr.flat().length <= 105
0 <= arr.flat()[i] <= 105
maxNestingDepth <= 105
Can you solve this without creating a new flattened version of the array?
type MultidimensionalArray = (MultidimensionalArray | number)[]
function* inorderTraversal(arr: MultidimensionalArray): Generator<number, void, unknown> {
for (const item of arr)
if (Array.isArray(item)) yield* inorderTraversal(item)
else yield item
}
/*
* const gen = inorderTraversal([1, [2, 3]]);
* gen.next().value; // 1
* gen.next().value; // 2
* gen.next().value; // 3
*/
export { inorderTraversal }