LeetCode in Kotlin
2621. Sleep
Easy
Given a positive integer millis, write an asynchronous function that sleeps for millis milliseconds. It can resolve any value.
Example 1:
Input: millis = 100
Output: 100
Explanation: It should return a promise that resolves after 100ms. let t = Date.now(); sleep(100).then(() => { console.log(Date.now() - t); // 100 });
Example 2:
Input: millis = 200
Output: 200
Explanation: It should return a promise that resolves after 200ms.
Constraints:
1 <= millis <= 1000
Solution
async function sleep(millis: number): Promise<void> {
await new Promise((resolve) => setTimeout(resolve, millis))
}
/*
* let t = Date.now()
* sleep(100).then(() => console.log(Date.now() - t)) // 100
*/
export { sleep }