LeetCode in Kotlin
2535. Difference Between Element Sum and Digit Sum of an Array
Easy
You are given a positive integer array nums.
- The element sum is the sum of all the elements in
nums. - The digit sum is the sum of all the digits (not necessarily distinct) that appear in
nums.
Return the absolute difference between the element sum and digit sum of nums.
Note that the absolute difference between two integers x and y is defined as |x - y|.
Example 1:
Input: nums = [1,15,6,3]
Output: 9
Explanation:
The element sum of nums is 1 + 15 + 6 + 3 = 25.
The digit sum of nums is 1 + 1 + 5 + 6 + 3 = 16.
The absolute difference between the element sum and digit sum is |25 - 16| = 9.
Example 2:
Input: nums = [1,2,3,4]
Output: 0
Explanation:
The element sum of nums is 1 + 2 + 3 + 4 = 10.
The digit sum of nums is 1 + 2 + 3 + 4 = 10.
The absolute difference between the element sum and digit sum is |10 - 10| = 0.
Constraints:
1 <= nums.length <= 20001 <= nums[i] <= 2000
Solution
@Suppress("NAME_SHADOWING")
class Solution {
private fun getsum(n: Int): Int {
var n = n
var sum = 0
while (n > 0) {
val r = n % 10
sum += r
n = n / 10
}
return sum
}
fun differenceOfSum(nums: IntArray): Int {
var eleSum = 0
var digitSum = 0
for (j in nums) {
digitSum += if (j >= 10) {
val sumC = getsum(j)
sumC
} else {
j
}
}
for (num in nums) {
eleSum += num
}
val max = Math.max(eleSum, digitSum)
val min = Math.min(eleSum, digitSum)
return max - min
}
}