LeetCode in Kotlin

2525. Categorize Box According to Criteria

Easy

Given four integers length, width, height, and mass, representing the dimensions and mass of a box, respectively, return a string representing the category of the box.

Note that the volume of the box is the product of its length, width and height.

Example 1:

Input: length = 1000, width = 35, height = 700, mass = 300

Output: “Heavy”

Explanation:

None of the dimensions of the box is greater or equal to 104.

Its volume = 24500000 <= 109. So it cannot be categorized as “Bulky”.

However mass >= 100, so the box is “Heavy”.

Since the box is not “Bulky” but “Heavy”, we return “Heavy”.

Example 2:

Input: length = 200, width = 50, height = 800, mass = 50

Output: “Neither”

Explanation:

None of the dimensions of the box is greater or equal to 104.

Its volume = 8 * 106 <= 109. So it cannot be categorized as “Bulky”.

Its mass is also less than 100, so it cannot be categorized as “Heavy” either.

Since its neither of the two above categories, we return “Neither”.

Constraints:

Solution

class Solution {
    fun categorizeBox(length: Int, width: Int, height: Int, mass: Int): String {
        val vol = length.toLong() * width * height
        var b = false
        var h = false
        if (length >= 10000 || width >= 10000 || height >= 10000 || vol >= 1000000000) {
            b = true
        }
        if (mass >= 100) {
            h = true
        }
        return if (b && h) {
            "Both"
        } else if (!b && !h) {
            "Neither"
        } else if (b) {
            "Bulky"
        } else {
            "Heavy"
        }
    }
}