LeetCode in Kotlin
2496. Maximum Value of a String in an Array
Easy
The value of an alphanumeric string can be defined as:
- The numeric representation of the string in base
10, if it comprises of digits only. - The length of the string, otherwise.
Given an array strs of alphanumeric strings, return the maximum value of any string in strs.
Example 1:
Input: strs = [“alic3”,”bob”,”3”,”4”,”00000”]
Output: 5
Explanation:
- “alic3” consists of both letters and digits, so its value is its length, i.e. 5.
- “bob” consists only of letters, so its value is also its length, i.e. 3.
- “3” consists only of digits, so its value is its numeric equivalent, i.e. 3.
- “4” also consists only of digits, so its value is 4.
- “00000” consists only of digits, so its value is 0.
Hence, the maximum value is 5, of “alic3”.
Example 2:
Input: strs = [“1”,”01”,”001”,”0001”]
Output: 1
Explanation: Each string in the array has value 1. Hence, we return 1.
Constraints:
1 <= strs.length <= 1001 <= strs[i].length <= 9strs[i]consists of only lowercase English letters and digits.
Solution
class Solution {
fun maximumValue(strs: Array<String>): Int {
var maxVal = 0
for (s in strs) {
maxVal = Math.max(maxVal, value(s))
}
return maxVal
}
private fun value(s: String): Int {
var total = 0
for (ch in s.toCharArray()) {
total = if (ch in '0'..'9') {
total * 10 + (ch.code - '0'.code)
} else {
return s.length
}
}
return total
}
}