Easy
Given an integer array nums
of positive integers, return the average value of all even integers that are divisible by 3
.
Note that the average of n
elements is the sum of the n
elements divided by n
and rounded down to the nearest integer.
Example 1:
Input: nums = [1,3,6,10,12,15]
Output: 9
Explanation: 6 and 12 are even numbers that are divisible by 3. (6 + 12) / 2 = 9.
Example 2:
Input: nums = [1,2,4,7,10]
Output: 0
Explanation: There is no single number that satisfies the requirement, so return 0.
Constraints:
1 <= nums.length <= 1000
1 <= nums[i] <= 1000
class Solution {
fun averageValue(nums: IntArray): Int {
var count = 0
var sum = 0
for (num in nums) {
if (num % 2 == 0 && num % 3 == 0) {
count++
sum += num
}
}
return if (count == 0) {
0
} else sum / count
}
}