LeetCode in Kotlin

2363. Merge Similar Items

Easy

You are given two 2D integer arrays, items1 and items2, representing two sets of items. Each array items has the following properties:

• items[i] = [valuei, weighti] where valuei represents the value and weighti represents the weight of the ith item.
• The value of each item in items is unique.

Return a 2D integer array ret where ret[i] = [valuei, weighti], with weighti being the sum of weights of all items with value valuei.

Note: ret should be returned in ascending order by value.

Example 1:

Input: items1 = [[1,1],[4,5],[3,8]], items2 = [[3,1],[1,5]]

Output: [[1,6],[3,9],[4,5]]

Explanation: The item with value = 1 occurs in items1 with weight = 1 and in items2 with weight = 5, total weight = 1 + 5 = 6.

The item with value = 3 occurs in items1 with weight = 8 and in items2 with weight = 1, total weight = 8 + 1 = 9.

The item with value = 4 occurs in items1 with weight = 5, total weight = 5.

Therefore, we return [[1,6],[3,9],[4,5]].

Example 2:

Input: items1 = [[1,1],[3,2],[2,3]], items2 = [[2,1],[3,2],[1,3]]

Output: [[1,4],[2,4],[3,4]]

Explanation: The item with value = 1 occurs in items1 with weight = 1 and in items2 with weight = 3, total weight = 1 + 3 = 4.

The item with value = 2 occurs in items1 with weight = 3 and in items2 with weight = 1, total weight = 3 + 1 = 4.

The item with value = 3 occurs in items1 with weight = 2 and in items2 with weight = 2, total weight = 2 + 2 = 4. Therefore, we return [[1,4],[2,4],[3,4]].

Example 3:

Input: items1 = [[1,3],[2,2]], items2 = [[7,1],[2,2],[1,4]]

Output: [[1,7],[2,4],[7,1]]

Explanation:

The item with value = 1 occurs in items1 with weight = 3 and in items2 with weight = 4, total weight = 3 + 4 = 7.

The item with value = 2 occurs in items1 with weight = 2 and in items2 with weight = 2, total weight = 2 + 2 = 4.

The item with value = 7 occurs in items2 with weight = 1, total weight = 1.

Therefore, we return [[1,7],[2,4],[7,1]].

Constraints:

• 1 <= items1.length, items2.length <= 1000
• items1[i].length == items2[i].length == 2
• 1 <= valuei, weighti <= 1000
• Each valuei in items1 is unique.
• Each valuei in items2 is unique.

Solution

class Solution {
    fun mergeSimilarItems(items1: Array<IntArray>, items2: Array<IntArray>): List<List<Int>> {
        val cache = IntArray(1001)
        for (num in items1) {
            cache[num[0]] += num[1]
        }
        for (num in items2) {
            cache[num[0]] += num[1]
        }
        val result: MutableList<List<Int>> = ArrayList()
        for (i in cache.indices) {
            val weight = cache[i]
            if (weight > 0) {
                result.add(listOf(i, weight))
            }
        }
        return result
    }
}

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