LeetCode in Kotlin

2357. Make Array Zero by Subtracting Equal Amounts

Easy

You are given a non-negative integer array nums. In one operation, you must:

• Choose a positive integer x such that x is less than or equal to the smallest non-zero element in nums.
• Subtract x from every positive element in nums.

Return the minimum number of operations to make every element in nums equal to 0.

Example 1:

Input: nums = [1,5,0,3,5]

Output: 3

Explanation:

In the first operation, choose x = 1. Now, nums = [0,4,0,2,4].

In the second operation, choose x = 2. Now, nums = [0,2,0,0,2].

In the third operation, choose x = 2. Now, nums = [0,0,0,0,0].

Example 2:

Input: nums = [0]

Output: 0

Explanation: Each element in nums is already 0 so no operations are needed.

Constraints:

• 1 <= nums.length <= 100
• 0 <= nums[i] <= 100

Solution

class Solution {
    fun minimumOperations(nums: IntArray): Int {
        val set: MutableSet<Int> = HashSet()
        for (a in nums) {
            if (a > 0) {
                set.add(a)
            }
        }
        return set.size
    }
}

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