Easy
A password is said to be strong if it satisfies all the following criteria:
8
characters."!@#$%^&*()-+"
.2
of the same character in adjacent positions (i.e., "aab"
violates this condition, but "aba"
does not).Given a string password
, return true
if it is a strong password. Otherwise, return false
.
Example 1:
Input: password = “IloveLe3tcode!”
Output: true
Explanation: The password meets all the requirements. Therefore, we return true.
Example 2:
Input: password = “Me+You–IsMyDream”
Output: false
Explanation: The password does not contain a digit and also contains 2 of the same character in adjacent positions. Therefore, we return false.
Example 3:
Input: password = “1aB!”
Output: false
Explanation: The password does not meet the length requirement. Therefore, we return false.
Constraints:
1 <= password.length <= 100
password
consists of letters, digits, and special characters: "!@#$%^&*()-+"
.class Solution {
fun strongPasswordCheckerII(password: String): Boolean {
if (password.length < 8) {
return false
}
var l = false
var u = false
var d = false
var s = false
val special = "!@#$%^&*()-+"
var previous = '.'
for (i in 0 until password.length) {
val ch = password[i]
if (ch == previous) {
return false
}
previous = ch
if (ch >= 'A' && ch <= 'Z') {
u = true
} else if (ch >= 'a' && ch <= 'z') {
l = true
} else if (ch >= '0' && ch <= '9') {
d = true
} else if (special.indexOf(ch) != -1) {
s = true
}
}
return l && u && d && s
}
}