LeetCode in Kotlin
2278. Percentage of Letter in String
Easy
Given a string s and a character letter, return the percentage of characters in s that equal letter rounded down to the nearest whole percent.
Example 1:
Input: s = “foobar”, letter = “o”
Output: 33
Explanation:
The percentage of characters in s that equal the letter ‘o’ is 2 / 6 * 100% = 33% when rounded down, so we return 33.
Example 2:
Input: s = “jjjj”, letter = “k”
Output: 0
Explanation:
The percentage of characters in s that equal the letter ‘k’ is 0%, so we return 0.
Constraints:
1 <= s.length <= 100sconsists of lowercase English letters.letteris a lowercase English letter.
Solution
class Solution {
fun percentageLetter(s: String, letter: Char): Int {
var count = 0
val n = s.length
for (i in 0 until n) {
if (s[i] == letter) {
++count
}
}
return count * 100 / n
}
}