LeetCode in Kotlin
2239. Find Closest Number to Zero
Easy
Given an integer array nums of size n, return the number with the value closest to 0 in nums. If there are multiple answers, return the number with the largest value.
Example 1:
Input: nums = [-4,-2,1,4,8]
Output: 1
Explanation:
The distance from -4 to 0 is |-4| = 4.
The distance from -2 to 0 is |-2| = 2.
The distance from 1 to 0 is |1| = 1. The distance from 4 to 0 is |4| = 4.
The distance from 8 to 0 is |8| = 8.
Thus, the closest number to 0 in the array is 1.
Example 2:
Input: nums = [2,-1,1]
Output: 1
Explanation: 1 and -1 are both the closest numbers to 0, so 1 being larger is returned.
Constraints:
1 <= n <= 1000-105 <= nums[i] <= 105
Solution
class Solution {
fun findClosestNumber(nums: IntArray): Int {
var mini = Int.MAX_VALUE
var closestNum = 0
for (n in nums) {
if (mini > Math.abs(n)) {
mini = Math.abs(n)
closestNum = n
} else if (mini == Math.abs(n) && closestNum < n) {
closestNum = n
}
}
return closestNum
}
}