LeetCode in Kotlin
2206. Divide Array Into Equal Pairs
Easy
You are given an integer array nums consisting of 2 * n integers.
You need to divide nums into n pairs such that:
- Each element belongs to exactly one pair.
- The elements present in a pair are equal.
Return true if nums can be divided into n pairs, otherwise return false.
Example 1:
Input: nums = [3,2,3,2,2,2]
Output: true
Explanation:
There are 6 elements in nums, so they should be divided into 6 / 2 = 3 pairs.
If nums is divided into the pairs (2, 2), (3, 3), and (2, 2), it will satisfy all the conditions.
Example 2:
Input: nums = [1,2,3,4]
Output: false
Explanation:
There is no way to divide nums into 4 / 2 = 2 pairs such that the pairs satisfy every condition.
Constraints:
nums.length == 2 * n1 <= n <= 5001 <= nums[i] <= 500
Solution
class Solution {
fun divideArray(nums: IntArray): Boolean {
val freq = IntArray(501)
for (num in nums) {
++freq[num]
}
for (f in freq) {
if (f % 2 != 0) {
return false
}
}
return true
}
}