LeetCode in Kotlin
2160. Minimum Sum of Four Digit Number After Splitting Digits
Easy
You are given a positive integer num consisting of exactly four digits. Split num into two new integers new1 and new2 by using the digits found in num. Leading zeros are allowed in new1 and new2, and all the digits found in num must be used.
- For example, given
num = 2932, you have the following digits: two2’s, one9and one3. Some of the possible pairs[new1, new2]are[22, 93],[23, 92],[223, 9]and[2, 329].
Return the minimum possible sum of new1 and new2.
Example 1:
Input: num = 2932
Output: 52
Explanation: Some possible pairs [new1, new2] are [29, 23], [223, 9], etc.
The minimum sum can be obtained by the pair [29, 23]: 29 + 23 = 52.
Example 2:
Input: num = 4009
Output: 13
Explanation: Some possible pairs [new1, new2] are [0, 49], [490, 0], etc.
The minimum sum can be obtained by the pair [4, 9]: 4 + 9 = 13.
Constraints:
1000 <= num <= 9999
Solution
@Suppress("NAME_SHADOWING")
class Solution {
fun minimumSum(num: Int): Int {
var num = num
val digit = IntArray(4)
var cur = 0
while (num > 0) {
digit[cur++] = num % 10
num /= 10
}
digit.sort()
val num1 = digit[0] * 10 + digit[2]
val num2 = digit[1] * 10 + digit[3]
return num1 + num2
}
}