LeetCode in Kotlin

2145. Count the Hidden Sequences

Medium

You are given a 0-indexed array of n integers differences, which describes the differences between each pair of consecutive integers of a hidden sequence of length (n + 1). More formally, call the hidden sequence hidden, then we have that differences[i] = hidden[i + 1] - hidden[i].

You are further given two integers lower and upper that describe the inclusive range of values [lower, upper] that the hidden sequence can contain.

• For example, given differences = [1, -3, 4], lower = 1, upper = 6, the hidden sequence is a sequence of length 4 whose elements are in between 1 and 6 (inclusive).
  • [3, 4, 1, 5] and [4, 5, 2, 6] are possible hidden sequences.
  • [5, 6, 3, 7] is not possible since it contains an element greater than 6.
  • [1, 2, 3, 4] is not possible since the differences are not correct.

Return the number of possible hidden sequences there are. If there are no possible sequences, return 0.

Example 1:

Input: differences = [1,-3,4], lower = 1, upper = 6

Output: 2

Explanation: The possible hidden sequences are:

• [3, 4, 1, 5]

• [4, 5, 2, 6]

Thus, we return 2.

Example 2:

Input: differences = [3,-4,5,1,-2], lower = -4, upper = 5

Output: 4

Explanation: The possible hidden sequences are:

• [-3, 0, -4, 1, 2, 0]

• [-2, 1, -3, 2, 3, 1]

• [-1, 2, -2, 3, 4, 2]

• [0, 3, -1, 4, 5, 3]

Thus, we return 4.

Example 3:

Input: differences = [4,-7,2], lower = 3, upper = 6

Output: 0

Explanation: There are no possible hidden sequences. Thus, we return 0.

Constraints:

• n == differences.length
• 1 <= n <= 105
• -105 <= differences[i] <= 105
• -105 <= lower <= upper <= 105

Solution

class Solution {
    fun numberOfArrays(differences: IntArray, lower: Int, upper: Int): Int {
        val n = differences.size
        if (lower == upper) {
            for (j in differences) {
                if (j != 0) {
                    return 0
                }
            }
        }
        var max = (-1e9).toInt()
        var min = 1e9.toInt()
        val hidden = IntArray(n + 1)
        hidden[0] = 0
        for (i in 1..n) {
            hidden[i] = hidden[i - 1] + differences[i - 1]
        }
        for (i in 0..n) {
            if (hidden[i] > max) {
                max = hidden[i]
            }
            if (hidden[i] < min) {
                min = hidden[i]
            }
        }
        val low = lower - min
        val high = upper - max
        return if (low > high) {
            0
        } else high - low + 1
    }
}

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