Medium
You are given a 0-indexed string s
and a 0-indexed integer array spaces
that describes the indices in the original string where spaces will be added. Each space should be inserted before the character at the given index.
s = "EnjoyYourCoffee"
and spaces = [5, 9]
, we place spaces before 'Y'
and 'C'
, which are at indices 5
and 9
respectively. Thus, we obtain "Enjoy **Y**our **C**offee"
.Return the modified string after the spaces have been added.
Example 1:
Input: s = “LeetcodeHelpsMeLearn”, spaces = [8,13,15]
Output: “Leetcode Helps Me Learn”
Explanation:
The indices 8, 13, and 15 correspond to the underlined characters in “LeetcodeHelpsMeLearn”.
We then place spaces before those characters.
Example 2:
Input: s = “icodeinpython”, spaces = [1,5,7,9]
Output: “i code in py thon”
Explanation:
The indices 1, 5, 7, and 9 correspond to the underlined characters in “icodeinpython”.
We then place spaces before those characters.
Example 3:
Input: s = “spacing”, spaces = [0,1,2,3,4,5,6]
Output: “ s p a c i n g”
Explanation: We are also able to place spaces before the first character of the string.
Constraints:
1 <= s.length <= 3 * 105
s
consists only of lowercase and uppercase English letters.1 <= spaces.length <= 3 * 105
0 <= spaces[i] <= s.length - 1
spaces
are strictly increasing.class Solution {
fun addSpaces(s: String, spaces: IntArray): String {
val stringChars = CharArray(s.length + spaces.size)
for (i in spaces.indices) {
stringChars[spaces[i] + i] = ' '
}
var equivalentIndex = -1
var i = 0
while (i < s.length) {
equivalentIndex++
if (stringChars[equivalentIndex] == ' ') {
i--
} else {
stringChars[equivalentIndex] = s[i]
}
i++
}
return String(stringChars)
}
}