LeetCode in Kotlin

1996. The Number of Weak Characters in the Game

Medium

You are playing a game that contains multiple characters, and each of the characters has two main properties: attack and defense. You are given a 2D integer array properties where properties[i] = [attacki, defensei] represents the properties of the ith character in the game.

A character is said to be weak if any other character has both attack and defense levels strictly greater than this character’s attack and defense levels. More formally, a character i is said to be weak if there exists another character j where attackj > attacki and defensej > defensei.

Return the number of weak characters.

Example 1:

Input: properties = [[5,5],[6,3],[3,6]]

Output: 0

Explanation: No character has strictly greater attack and defense than the other.

Example 2:

Input: properties = [[2,2],[3,3]]

Output: 1

Explanation: The first character is weak because the second character has a strictly greater attack and defense.

Example 3:

Input: properties = [[1,5],[10,4],[4,3]]

Output: 1

Explanation: The third character is weak because the second character has a strictly greater attack and defense.

Constraints:

Solution

class Solution {
    fun numberOfWeakCharacters(properties: Array<IntArray>): Int {
        properties.sortWith { a: IntArray, b: IntArray -> if (a[0] == b[0]) b[1] - a[1] else a[0] - b[0] }
        var max = properties[properties.size - 1][1]
        var count = 0
        for (i in properties.size - 2 downTo 0) {
            if (properties[i][1] < max) {
                count++
            }
            max = Math.max(max, properties[i][1])
        }
        return count
    }
}