LeetCode in Kotlin
1978. Employees Whose Manager Left the Company
Easy
SQL Schema
Table: Employees
+-------------+----------+
| Column Name | Type |
+-------------+----------+
| employee_id | int |
| name | varchar |
| manager_id | int |
| salary | int |
+-------------+----------+
employee_id is the primary key for this table. This table contains information about the employees, their salary, and the ID of their manager. Some employees do not have a manager (manager_id is null).
Write an SQL query to report the IDs of the employees whose salary is strictly less than $30000 and whose manager left the company. When a manager leaves the company, their information is deleted from the Employees table, but the reports still have their manager_id set to the manager that left.
Return the result table ordered by employee_id.
The query result format is in the following example.
Example 1:
**Input: ** Employees table:
+-------------+-----------+------------+--------+
| employee_id | name | manager_id | salary |
+-------------+-----------+------------+--------+
| 3 | Mila | 9 | 60301 |
| 12 | Antonella | null | 31000 |
| 13 | Emery | null | 67084 |
| 1 | Kalel | 11 | 21241 |
| 9 | Mikaela | null | 50937 |
| 11 | Joziah | 6 | 28485 |
+-------------+-----------+------------+--------+
Output:
+-------------+
| employee_id |
+-------------+
| 11 |
+-------------+
Explanation:
The employees with a salary less than $30000 are 1 (Kalel) and 11 (Joziah).
Kalel’s manager is employee 11, who is still in the company (Joziah).
Joziah’s manager is employee 6, who left the company because there is no row for employee 6 as it was deleted.
Solution
# Write your MySQL query statement below
select employee_id from employees where manager_id not in (select distinct (employee_id) from employees)
AND salary < 30000 order by employee_id