Medium
There is a party where n
friends numbered from 0
to n - 1
are attending. There is an infinite number of chairs in this party that are numbered from 0
to infinity
. When a friend arrives at the party, they sit on the unoccupied chair with the smallest number.
0
, 1
, and 5
are occupied when a friend comes, they will sit on chair number 2
.When a friend leaves the party, their chair becomes unoccupied at the moment they leave. If another friend arrives at that same moment, they can sit in that chair.
You are given a 0-indexed 2D integer array times
where times[i] = [arrivali, leavingi]
, indicating the arrival and leaving times of the ith
friend respectively, and an integer targetFriend
. All arrival times are distinct.
Return the chair number that the friend numbered targetFriend
will sit on.
Example 1:
Input: times = [[1,4],[2,3],[4,6]], targetFriend = 1
Output: 1
Explanation:
Friend 0 arrives at time 1 and sits on chair 0.
Friend 1 arrives at time 2 and sits on chair 1.
Friend 1 leaves at time 3 and chair 1 becomes empty.
Friend 0 leaves at time 4 and chair 0 becomes empty.
Friend 2 arrives at time 4 and sits on chair 0.
Since friend 1 sat on chair 1, we return 1.
Example 2:
Input: times = [[3,10],[1,5],[2,6]], targetFriend = 0
Output: 2
Explanation:
Friend 1 arrives at time 1 and sits on chair 0.
Friend 2 arrives at time 2 and sits on chair 1.
Friend 0 arrives at time 3 and sits on chair 2.
Friend 1 leaves at time 5 and chair 0 becomes empty.
Friend 2 leaves at time 6 and chair 1 becomes empty.
Friend 0 leaves at time 10 and chair 2 becomes empty.
Since friend 0 sat on chair 2, we return 2.
Constraints:
n == times.length
2 <= n <= 104
times[i].length == 2
1 <= arrivali < leavingi <= 105
0 <= targetFriend <= n - 1
arrivali
time is distinct.import java.util.PriorityQueue
class Solution {
fun smallestChair(times: Array<IntArray>, targetFriend: Int): Int {
val minheap = PriorityQueue<Int>()
minheap.offer(0)
val all = arrayOfNulls<Person>(times.size * 2)
for (i in times.indices) {
all[2 * i] = Person(i, times[i][0], false, true)
all[2 * i + 1] = Person(i, times[i][1], true, false)
}
all.sortWith { a: Person?, b: Person? ->
val i = if (a!!.leave) -1 else 1
val j = if (b!!.leave) -1 else 1
if (a.time == b.time) i - j else a.time - b.time
}
val seat = IntArray(times.size)
var i = 0
while (true) {
if (all[i]!!.arrive) {
if (targetFriend == all[i]!!.idx) {
return minheap.peek()
}
seat[all[i]!!.idx] = minheap.poll()
if (minheap.isEmpty()) {
minheap.offer(seat[all[i]!!.idx] + 1)
}
} else {
minheap.offer(seat[all[i]!!.idx])
}
i++
}
}
private class Person internal constructor(var idx: Int, var time: Int, var leave: Boolean, var arrive: Boolean)
}