Easy
You are given a string num
, representing a large integer. Return the largest-valued odd integer (as a string) that is a non-empty substring of num
, or an empty string ""
if no odd integer exists.
A substring is a contiguous sequence of characters within a string.
Example 1:
Input: num = “52”
Output: “5”
Explanation: The only non-empty substrings are “5”, “2”, and “52”. “5” is the only odd number.
Example 2:
Input: num = “4206”
Output: “”
Explanation: There are no odd numbers in “4206”.
Example 3:
Input: num = “35427”
Output: “35427”
Explanation: “35427” is already an odd number.
Constraints:
1 <= num.length <= 105
num
only consists of digits and does not contain any leading zeros.class Solution {
fun largestOddNumber(num: String): String {
for (i in num.length - 1 downTo 0) {
if (("" + num[i]).toInt() % 2 == 1) {
return num.substring(0, i + 1)
}
}
return ""
}
}