Medium
Given n
points
on a 2D plane where points[i] = [xi, yi]
, Return_ the widest vertical area between two points such that no points are inside the area._
A vertical area is an area of fixed-width extending infinitely along the y-axis (i.e., infinite height). The widest vertical area is the one with the maximum width.
Note that points on the edge of a vertical area are not considered included in the area.
Example 1:
Input: points = [[8,7],[9,9],[7,4],[9,7]]
Output: 1
Explanation: Both the red and the blue area are optimal.
Example 2:
Input: points = [[3,1],[9,0],[1,0],[1,4],[5,3],[8,8]]
Output: 3
Constraints:
n == points.length
2 <= n <= 105
points[i].length == 2
0 <= xi, yi <= 109
class Solution {
fun maxWidthOfVerticalArea(points: Array<IntArray>): Int {
val xValues = IntArray(points.size)
for (i in points.indices) {
xValues[i] = points[i][0]
}
xValues.sort()
var max = 0
for (j in 0 until xValues.size - 1) {
if (xValues[j + 1] - xValues[j] > max) {
max = xValues[j + 1] - xValues[j]
}
}
return max
}
}