Medium
LeetCode company workers use key-cards to unlock office doors. Each time a worker uses their key-card, the security system saves the worker’s name and the time when it was used. The system emits an alert if any worker uses the key-card three or more times in a one-hour period.
You are given a list of strings keyName
and keyTime
where [keyName[i], keyTime[i]]
corresponds to a person’s name and the time when their key-card was used in a single day.
Access times are given in the 24-hour time format “HH:MM”, such as "23:51"
and "09:49"
.
Return a list of unique worker names who received an alert for frequent keycard use. Sort the names in ascending order alphabetically.
Notice that "10:00"
- "11:00"
is considered to be within a one-hour period, while "22:51"
- "23:52"
is not considered to be within a one-hour period.
Example 1:
Input: keyName = [“daniel”,”daniel”,”daniel”,”luis”,”luis”,”luis”,”luis”], keyTime = [“10:00”,”10:40”,”11:00”,”09:00”,”11:00”,”13:00”,”15:00”]
Output: [“daniel”]
Explanation: “daniel” used the keycard 3 times in a one-hour period (“10:00”,”10:40”, “11:00”).
Example 2:
Input: keyName = [“alice”,”alice”,”alice”,”bob”,”bob”,”bob”,”bob”], keyTime = [“12:01”,”12:00”,”18:00”,”21:00”,”21:20”,”21:30”,”23:00”]
Output: [“bob”]
Explanation: “bob” used the keycard 3 times in a one-hour period (“21:00”,”21:20”, “21:30”).
Constraints:
1 <= keyName.length, keyTime.length <= 105
keyName.length == keyTime.length
keyTime[i]
is in the format “HH:MM”.[keyName[i], keyTime[i]]
is unique.1 <= keyName[i].length <= 10
keyName[i] contains only lowercase English letters.
class Solution {
fun alertNames(keyName: Array<String>, keyTime: Array<String>): List<String> {
val map = HashMap<String, MutableList<String>>()
for (i in keyName.indices) {
map.putIfAbsent(keyName[i], ArrayList())
map[keyName[i]]!!.add(keyTime[i])
}
val soln: MutableList<String> = ArrayList()
for ((key, timeStamps) in map) {
timeStamps.sort()
var i = 0
while (i + 2 < timeStamps.size) {
val first = timeStamps[i].split(":").dropLastWhile { it.isEmpty() }.toTypedArray()
val third = timeStamps[i + 2].split(":").dropLastWhile { it.isEmpty() }.toTypedArray()
val hourDiff = third[0].toInt() - first[0].toInt()
val minDiff = third[1].toInt() - first[1].toInt()
if (hourDiff == 0 || hourDiff == 1 && minDiff <= 0) {
soln.add(key)
break
}
i++
}
}
soln.sort()
return soln
}
}