LeetCode in Kotlin

1568. Minimum Number of Days to Disconnect Island

Hard

You are given an m x n binary grid grid where 1 represents land and 0 represents water. An island is a maximal 4-directionally (horizontal or vertical) connected group of 1’s.

The grid is said to be connected if we have exactly one island, otherwise is said disconnected.

In one day, we are allowed to change any single land cell (1) into a water cell (0).

Return the minimum number of days to disconnect the grid.

Example 1:

Input: grid = [[0,1,1,0],[0,1,1,0],[0,0,0,0]]

Output: 2

Explanation: We need at least 2 days to get a disconnected grid. Change land grid[1][1] and grid[0][2] to water and get 2 disconnected island.

Example 2:

Input: grid = [[1,1]]

Output: 2

Explanation: Grid of full water is also disconnected ([[1,1]] -> [[0,0]]), 0 islands.

Constraints:

• m == grid.length
• n == grid[i].length
• 1 <= m, n <= 30
• grid[i][j] is either 0 or 1.

Solution

@Suppress("kotlin:S107")
class Solution {
    private val dirs = arrayOf(intArrayOf(0, 1), intArrayOf(0, -1), intArrayOf(1, 0), intArrayOf(-1, 0))
    fun minDays(grid: Array<IntArray>): Int {
        val m = grid.size
        val n = grid[0].size
        var numOfIslands = 0
        var hasArticulationPoint = false
        var color = 1
        var minIslandSize = m * n
        val time = Array(m) { IntArray(n) }
        val low = Array(m) { IntArray(n) }
        for (i in 0 until m) {
            for (j in 0 until n) {
                if (grid[i][j] == 1) {
                    numOfIslands++
                    color++
                    val articulationPoints: MutableList<Int> = ArrayList()
                    val islandSize = IntArray(1)
                    tarjan(i, j, -1, -1, 0, time, low, grid, articulationPoints, color, islandSize)
                    minIslandSize = Math.min(minIslandSize, islandSize[0])
                    if (articulationPoints.isNotEmpty()) {
                        hasArticulationPoint = true
                    }
                }
            }
        }
        if (numOfIslands >= 2) {
            return 0
        }
        if (numOfIslands == 0) {
            return 0
        }
        if (numOfIslands == 1 && minIslandSize == 1) {
            return 1
        }
        return if (hasArticulationPoint) 1 else 2
    }

    private fun tarjan(
        x: Int,
        y: Int,
        prex: Int,
        prey: Int,
        time: Int,
        times: Array<IntArray>,
        lows: Array<IntArray>,
        grid: Array<IntArray>,
        articulationPoints: MutableList<Int>,
        color: Int,
        islandSize: IntArray
    ) {
        times[x][y] = time
        lows[x][y] = time
        grid[x][y] = color
        islandSize[0]++
        var children = 0
        for (dir in dirs) {
            val nx = x + dir[0]
            val ny = y + dir[1]
            if (nx < 0 || ny < 0 || nx >= grid.size || ny >= grid[0].size) {
                continue
            }
            if (grid[nx][ny] == 1) {
                children++
                tarjan(
                    nx,
                    ny,
                    x,
                    y,
                    time + 1,
                    times,
                    lows,
                    grid,
                    articulationPoints,
                    color,
                    islandSize
                )
                lows[x][y] = Math.min(lows[x][y], lows[nx][ny])
                if (prex != -1 && lows[nx][ny] >= time) {
                    articulationPoints.add(x * grid.size + y)
                }
            } else if ((nx != prex || ny != prey) && grid[nx][ny] != 0) {
                lows[x][y] = Math.min(lows[x][y], times[nx][ny])
            }
        }
        if (prex == -1 && children > 1) {
            articulationPoints.add(x * grid.size + y)
        }
    }
}

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