LeetCode in Kotlin
1550. Three Consecutive Odds
Easy
Given an integer array arr, return true if there are three consecutive odd numbers in the array. Otherwise, return false.
Example 1:
Input: arr = [2,6,4,1]
Output: false
Explanation: There are no three consecutive odds.
Example 2:
Input: arr = [1,2,34,3,4,5,7,23,12]
Output: true
Explanation: [5,7,23] are three consecutive odds.
Constraints:
1 <= arr.length <= 10001 <= arr[i] <= 1000
Solution
class Solution {
fun threeConsecutiveOdds(arr: IntArray): Boolean {
for (i in 0 until arr.size - 2) {
if (arr[i] % 2 == 1 && arr[i + 1] % 2 == 1 && arr[i + 2] % 2 == 1) {
return true
}
}
return false
}
}