LeetCode in Kotlin
1535. Find the Winner of an Array Game
Medium
Given an integer array arr of distinct integers and an integer k.
A game will be played between the first two elements of the array (i.e. arr[0] and arr[1]). In each round of the game, we compare arr[0] with arr[1], the larger integer wins and remains at position 0, and the smaller integer moves to the end of the array. The game ends when an integer wins k consecutive rounds.
Return the integer which will win the game.
It is guaranteed that there will be a winner of the game.
Example 1:
Input: arr = [2,1,3,5,4,6,7], k = 2
Output: 5
Explanation: Let’s see the rounds of the game:
Round | arr | winner | win_count
1 | [2,1,3,5,4,6,7] | 2 | 1
2 | [2,3,5,4,6,7,1] | 3 | 1
3 | [3,5,4,6,7,1,2] | 5 | 1
4 | [5,4,6,7,1,2,3] | 5 | 2
So we can see that 4 rounds will be played and 5 is the winner because it wins 2 consecutive games.
Example 2:
Input: arr = [3,2,1], k = 10
Output: 3
Explanation: 3 will win the first 10 rounds consecutively.
Constraints:
2 <= arr.length <= 1051 <= arr[i] <= 106arrcontains distinct integers.1 <= k <= 109
Solution
class Solution {
fun getWinner(arr: IntArray, k: Int): Int {
var winner = arr[0]
var winTimes = 0
for (i in 1 until arr.size) {
if (arr[i] > winner) {
winner = arr[i]
winTimes = 1
} else {
winTimes++
}
if (winTimes >= k) {
return winner
}
}
return winner
}
}