LeetCode in Kotlin
1534. Count Good Triplets
Easy
Given an array of integers arr, and three integers a, b and c. You need to find the number of good triplets.
A triplet (arr[i], arr[j], arr[k]) is good if the following conditions are true:
0 <= i < j < k < arr.length|arr[i] - arr[j]| <= a|arr[j] - arr[k]| <= b|arr[i] - arr[k]| <= c
Where |x| denotes the absolute value of x.
Return the number of good triplets.
Example 1:
Input: arr = [3,0,1,1,9,7], a = 7, b = 2, c = 3
Output: 4
Explanation: There are 4 good triplets: [(3,0,1), (3,0,1), (3,1,1), (0,1,1)].
Example 2:
Input: arr = [1,1,2,2,3], a = 0, b = 0, c = 1
Output: 0
Explanation: No triplet satisfies all conditions.
Constraints:
3 <= arr.length <= 1000 <= arr[i] <= 10000 <= a, b, c <= 1000
Solution
class Solution {
fun countGoodTriplets(arr: IntArray, a: Int, b: Int, c: Int): Int {
var count = 0
for (i in 0 until arr.size - 2) {
for (j in i + 1 until arr.size - 1) {
if (Math.abs(arr[i] - arr[j]) <= a) {
for (k in j + 1 until arr.size) {
if (Math.abs(arr[j] - arr[k]) <= b && Math.abs(arr[i] - arr[k]) <= c) {
count++
}
}
}
}
}
return count
}
}