LeetCode in Kotlin
1523. Count Odd Numbers in an Interval Range
Easy
Given two non-negative integers low and high. Return the count of odd numbers between low and high_ (inclusive)_.
Example 1:
Input: low = 3, high = 7
Output: 3
Explanation: The odd numbers between 3 and 7 are [3,5,7].
Example 2:
Input: low = 8, high = 10
Output: 1
Explanation: The odd numbers between 8 and 10 are [9].
Constraints:
0 <= low <= high <= 10^9
Solution
class Solution {
fun countOdds(low: Int, high: Int): Int {
return if (low % 2 != 0 || high % 2 != 0) {
(high - low) / 2 + 1
} else (high - low) / 2
}
}