LeetCode in Kotlin

1507. Reformat Date

Easy

Given a date string in the form Day Month Year, where:

• Day is in the set {"1st", "2nd", "3rd", "4th", ..., "30th", "31st"}.
• Month is in the set {"Jan", "Feb", "Mar", "Apr", "May", "Jun", "Jul", "Aug", "Sep", "Oct", "Nov", "Dec"}.
• Year is in the range [1900, 2100].

Convert the date string to the format YYYY-MM-DD, where:

• YYYY denotes the 4 digit year.
• MM denotes the 2 digit month.
• DD denotes the 2 digit day.

Example 1:

Input: date = “20th Oct 2052”

Output: “2052-10-20”

Example 2:

Input: date = “6th Jun 1933”

Output: “1933-06-06”

Example 3:

Input: date = “26th May 1960”

Output: “1960-05-26”

Constraints:

• The given dates are guaranteed to be valid, so no error handling is necessary.

Solution

class Solution {
    fun reformatDate(date: String): String {
        val sb = StringBuilder()
        val map: MutableMap<String, String> = HashMap()
        map["Jan"] = "01"
        map["Feb"] = "02"
        map["Mar"] = "03"
        map["Apr"] = "04"
        map["May"] = "05"
        map["Jun"] = "06"
        map["Jul"] = "07"
        map["Aug"] = "08"
        map["Sep"] = "09"
        map["Oct"] = "10"
        map["Nov"] = "11"
        map["Dec"] = "12"
        sb.append(date.substring(date.length - 4))
        sb.append('-')
        sb.append(map[date.substring(date.length - 8, date.length - 5)])
        sb.append('-')
        if (Character.isDigit(date[1])) {
            sb.append(date, 0, 2)
        } else {
            sb.append('0')
            sb.append(date[0])
        }
        return sb.toString()
    }
}

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