Medium
Given an array of integers arr
of even length n
and an integer k
.
We want to divide the array into exactly n / 2
pairs such that the sum of each pair is divisible by k
.
Return true
If you can find a way to do that or false
otherwise.
Example 1:
Input: arr = [1,2,3,4,5,10,6,7,8,9], k = 5
Output: true
Explanation: Pairs are (1,9),(2,8),(3,7),(4,6) and (5,10).
Example 2:
Input: arr = [1,2,3,4,5,6], k = 7
Output: true
Explanation: Pairs are (1,6),(2,5) and(3,4).
Example 3:
Input: arr = [1,2,3,4,5,6], k = 10
Output: false
Explanation: You can try all possible pairs to see that there is no way to divide arr into 3 pairs each with sum divisible by 10.
Constraints:
arr.length == n
1 <= n <= 105
n
is even.-109 <= arr[i] <= 109
1 <= k <= 105
class Solution {
fun canArrange(arr: IntArray, k: Int): Boolean {
val freq = IntArray(k)
for (num in arr) {
freq[Math.abs(num % k + k) % k]++
}
if (freq[0] % 2 != 0) {
return false
}
for (i in 1..k / 2) {
if (i == k - i && freq[i] % 2 != 0) {
return false
}
if (freq[i] != freq[k - i]) {
return false
}
}
return true
}
}