Easy
You are given an array of unique integers salary
where salary[i]
is the salary of the ith
employee.
Return the average salary of employees excluding the minimum and maximum salary. Answers within 10-5
of the actual answer will be accepted.
Example 1:
Input: salary = [4000,3000,1000,2000]
Output: 2500.00000
Explanation: Minimum salary and maximum salary are 1000 and 4000 respectively.
Average salary excluding minimum and maximum salary is (2000+3000) / 2 = 2500
Example 2:
Input: salary = [1000,2000,3000]
Output: 2000.00000
Explanation: Minimum salary and maximum salary are 1000 and 3000 respectively.
Average salary excluding minimum and maximum salary is (2000) / 1 = 2000
Constraints:
3 <= salary.length <= 100
1000 <= salary[i] <= 106
salary
are unique.class Solution {
fun average(salary: IntArray): Double {
val n = salary.size
var min = salary[0]
var max = salary[0]
var sum = salary[0]
for (i in 1 until n) {
if (salary[i] < min) {
min = salary[i]
} else if (salary[i] > max) {
max = salary[i]
}
sum += salary[i]
}
return (sum - min - max).toDouble() / (n - 2)
}
}