LeetCode in Kotlin

1460. Make Two Arrays Equal by Reversing Sub-arrays

Easy

You are given two integer arrays of equal length target and arr. In one step, you can select any non-empty sub-array of arr and reverse it. You are allowed to make any number of steps.

Return true if you can make arr equal to targetor false otherwise.

Example 1:

Input: target = [1,2,3,4], arr = [2,4,1,3]

Output: true

Explanation: You can follow the next steps to convert arr to target:

1- Reverse sub-array [2,4,1], arr becomes [1,4,2,3]

2- Reverse sub-array [4,2], arr becomes [1,2,4,3]

3- Reverse sub-array [4,3], arr becomes [1,2,3,4]

There are multiple ways to convert arr to target, this is not the only way to do so.

Example 2:

Input: target = [7], arr = [7]

Output: true

Explanation: arr is equal to target without any reverses.

Example 3:

Input: target = [3,7,9], arr = [3,7,11]

Output: false

Explanation: arr does not have value 9 and it can never be converted to target.

Constraints:

• target.length == arr.length
• 1 <= target.length <= 1000
• 1 <= target[i] <= 1000
• 1 <= arr[i] <= 1000

Solution

class Solution {
    fun canBeEqual(target: IntArray, arr: IntArray): Boolean {
        val n = target.size
        target.sort()
        arr.sort()
        var count = 0
        for (i in target.indices) {
            if (target[i] == arr[i]) {
                count++
            }
        }
        return count == n
    }
}

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