LeetCode in Kotlin
1455. Check If a Word Occurs As a Prefix of Any Word in a Sentence
Easy
Given a sentence that consists of some words separated by a single space, and a searchWord, check if searchWord is a prefix of any word in sentence.
Return the index of the word in sentence (1-indexed) where searchWord is a prefix of this word. If searchWord is a prefix of more than one word, return the index of the first word (minimum index). If there is no such word return -1.
A prefix of a string s is any leading contiguous substring of s.
Example 1:
Input: sentence = “i love eating burger”, searchWord = “burg”
Output: 4
Explanation: “burg” is prefix of “burger” which is the 4th word in the sentence.
Example 2:
Input: sentence = “this problem is an easy problem”, searchWord = “pro”
Output: 2
Explanation: “pro” is prefix of “problem” which is the 2nd and the 6th word in the sentence, but we return 2 as it’s the minimal index.
Example 3:
Input: sentence = “i am tired”, searchWord = “you”
Output: -1
Explanation: “you” is not a prefix of any word in the sentence.
Constraints:
1 <= sentence.length <= 1001 <= searchWord.length <= 10sentenceconsists of lowercase English letters and spaces.searchWordconsists of lowercase English letters.
Solution
class Solution {
fun isPrefixOfWord(sentence: String, searchWord: String): Int {
val words = sentence.split(" ").dropLastWhile { it.isEmpty() }.toTypedArray()
for (i in words.indices) {
if (words[i].startsWith(searchWord)) {
return i + 1
}
}
return -1
}
}