LeetCode in Kotlin
1450. Number of Students Doing Homework at a Given Time
Easy
Given two integer arrays startTime and endTime and given an integer queryTime.
The ith student started doing their homework at the time startTime[i] and finished it at time endTime[i].
Return the number of students doing their homework at time queryTime. More formally, return the number of students where queryTime lays in the interval [startTime[i], endTime[i]] inclusive.
Example 1:
Input: startTime = [1,2,3], endTime = [3,2,7], queryTime = 4
Output: 1
Explanation: We have 3 students where:
The first student started doing homework at time 1 and finished at time 3 and wasn’t doing anything at time 4.
The second student started doing homework at time 2 and finished at time 2 and also wasn’t doing anything at time 4.
The third student started doing homework at time 3 and finished at time 7 and was the only student doing homework at time 4.
Example 2:
Input: startTime = [4], endTime = [4], queryTime = 4
Output: 1
Explanation: The only student was doing their homework at the queryTime.
Constraints:
startTime.length == endTime.length1 <= startTime.length <= 1001 <= startTime[i] <= endTime[i] <= 10001 <= queryTime <= 1000
Solution
class Solution {
fun busyStudent(startTime: IntArray, endTime: IntArray, queryTime: Int): Int {
var count = 0
for (i in startTime.indices) {
if (startTime[i] <= queryTime && endTime[i] >= queryTime) {
count++
}
}
return count
}
}