LeetCode in Kotlin

1431. Kids With the Greatest Number of Candies

Easy

There are n kids with candies. You are given an integer array candies, where each candies[i] represents the number of candies the ith kid has, and an integer extraCandies, denoting the number of extra candies that you have.

Return a boolean array result of length n, where result[i] is true if, after giving the ith kid all the extraCandies, they will have the greatest number of candies among all the kids__, or false otherwise.

Note that multiple kids can have the greatest number of candies.

Example 1:

Input: candies = [2,3,5,1,3], extraCandies = 3

Output: [true,true,true,false,true]

Explanation: If you give all extraCandies to:

• Kid 1, they will have 2 + 3 = 5 candies, which is the greatest among the kids.
• Kid 2, they will have 3 + 3 = 6 candies, which is the greatest among the kids.
• Kid 3, they will have 5 + 3 = 8 candies, which is the greatest among the kids.
• Kid 4, they will have 1 + 3 = 4 candies, which is not the greatest among the kids.
• Kid 5, they will have 3 + 3 = 6 candies, which is the greatest among the kids.

Example 2:

Input: candies = [4,2,1,1,2], extraCandies = 1

Output: [true,false,false,false,false]

Explanation: There is only 1 extra candy. Kid 1 will always have the greatest number of candies, even if a different kid is given the extra candy.

Example 3:

Input: candies = [12,1,12], extraCandies = 10

Output: [true,false,true]

Constraints:

• n == candies.length
• 2 <= n <= 100
• 1 <= candies[i] <= 100
• 1 <= extraCandies <= 50

Solution

class Solution {
    fun kidsWithCandies(candies: IntArray, extraCandies: Int): List<Boolean> {
        var max = 0
        for (i in candies) {
            max = Math.max(max, i)
        }
        val result: MutableList<Boolean> = ArrayList()
        for (candy in candies) {
            result.add(candy + extraCandies >= max)
        }
        return result
    }
}

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