Hard
A chef has collected data on the satisfaction
level of his n
dishes. Chef can cook any dish in 1 unit of time.
Like-time coefficient of a dish is defined as the time taken to cook that dish including previous dishes multiplied by its satisfaction level i.e. time[i] * satisfaction[i]
.
Return the maximum sum of like-time coefficient that the chef can obtain after dishes preparation.
Dishes can be prepared in any order and the chef can discard some dishes to get this maximum value.
Example 1:
Input: satisfaction = [-1,-8,0,5,-9]
Output: 14
Explanation: After Removing the second and last dish, the maximum total like-time coefficient will be equal to (-1*1 + 0*2 + 5*3 = 14). Each dish is prepared in one unit of time.
Example 2:
Input: satisfaction = [4,3,2]
Output: 20
Explanation: Dishes can be prepared in any order, (2*1 + 3*2 + 4*3 = 20)
Example 3:
Input: satisfaction = [-1,-4,-5]
Output: 0
Explanation: People do not like the dishes. No dish is prepared.
Constraints:
n == satisfaction.length
1 <= n <= 500
-1000 <= satisfaction[i] <= 1000
class Solution {
fun maxSatisfaction(satisfaction: IntArray): Int {
satisfaction.sort()
var sum = 0
var mulSum = 0
for (i in satisfaction.indices) {
sum += satisfaction[i]
mulSum += (i + 1) * satisfaction[i]
}
var maxVal = Math.max(0, mulSum)
for (j in satisfaction) {
mulSum -= sum
sum -= j
maxVal = Math.max(maxVal, mulSum)
}
return maxVal
}
}